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C语言编写程序,将一个5 x 5矩阵转置后输出

可以参照如图所示的代码:

#include void main(){int i,j,t,a[5][5];for(i=0;i

#include using namespace std; void trans(int m[5][5]) {int i,j,k; for(i=0;i

可以如下操作: int[][] num = new int [5][3]; //num为5*3的二位数组 init(num); //为num数组负值 for(int i=0;i

#include #include using namespace std; void Init(int a[][5], int n) { int i,j; for(i=0;i

#include #include #include void changeArrayData(int *arrayAddress1, int *arrayAddress2); int main( void) { int array[5][5] = {0}; int i = 0, j = 0; int *arrayMax = 0, *arrayMin[4] = {array[0], array[0]+4, array[4], array[4]+4};...

package table;public class Rect{public static void main ( String[] args ){int[][] orial = {{1,2,3,4,5}, {6,7,8,9,10}, {11,12,13,14,15}, {16,17,18,19,20}, {21,22,23,24,25}};for ( int[] is : orial ){for ( int i : is ){System.out....

#include int main() { int i, b[5],j; printf("输入5个数:"); for (i = 0; i < 5; i++) scanf("%d",&b[i]); printf("5个数是:"); for (i = 0; i < 5; i++) printf("%5d",b[i]); }这是第一个题 #include void sort(int *a, int n) { int t; for ...

#include void main(){ int i, j; float a[5], aver, t, s = 0.0; printf ("输入五个数:\n"); for (i = 0; i < 5; i++) { scanf ("%f", &a[i]); s += a[i]; } aver = s / 5; printf ("这五个数的平均数:%f\n", aver); printf ("排序后:\n"); ...

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