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C语言编写程序,将一个5 x 5矩阵转置后输出

可以参照如图所示的代码:

#include void main(){int i,j,t,a[5][5];for(i=0;i

#include #include using namespace std; void Init(int a[][5], int n) { int i,j; for(i=0;i

#include int main() { int i, b[5],j; printf("输入5个数:"); for (i = 0; i < 5; i++) scanf("%d",&b[i]); printf("5个数是:"); for (i = 0; i < 5; i++) printf("%5d",b[i]); }这是第一个题 #include void sort(int *a, int n) { int t; for ...

#includeint main(){int a[5][5],trans[5][5],b[5][2],c[5][2],sum=0,i,j,k,temp;for(i=0;i

package table;public class Rect{public static void main ( String[] args ){int[][] orial = {{1,2,3,4,5}, {6,7,8,9,10}, {11,12,13,14,15}, {16,17,18,19,20}, {21,22,23,24,25}};for ( int[] is : orial ){for ( int i : is ){System.out....

效果如图 ---------------------- public class TestArray { public static void method(int[][] array) { for (int i = 0; i < array.length; i++) { for(int j=0;j

#include "stdio.h"#define N 5void transpose(int (*p)[N]){int i,j;for(i=0;i

#include void main() { char ch; printf("Please input the letter:\n"); scanf("%c",&ch) ; if (ch=((ch>='a')&&(ch='v')&&(ch

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